Class 6 Maths Chapter 1 - Knowing Our Numbers.

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# Class 6 Maths Chapter 1 - Knowing Our Numbers.

- Watch this Video For Complete Explanation -

In the previous classes, we have learnt about Comparing and reordering of numbers, Rounding off numbers to nearest ten and we have also learnt about some basic mathematical operations like Addition, Subtraction, Multiplication and Division. Now, we will study more about Numbers, their properties and operations. Like making larger numbers, reordering and expansion of larger numbers, Numeration, Estimation and we will also learn about Roman Numbers.

- COMPLETE STUDY MATERIAL -

Here at MSEducator.in you get Complete FREE Study Material for Class 6 Maths Chapter 1 : Knowing Our Numbers.

Which Includes :-

# Class 6 Maths Chapter 1 Video Explanation.

# Class 6 Maths Chapter 1 NCERT Sol. Ex - 1.1

# Class 6 Maths Chapter 1 NCERT Sol. Ex - 1.2

# Class 6 Maths Chapter 1 Important Q's.

# Class 6 Maths Chapter 1 Fill in the Blanks.

# Class 6 Maths Chapter 1 True - False.

# Class 6 Maths Chapter 1 MCQ Test.

# Click here to get Complete Study Material for Class 6 Maths Chapter 1 : Knowing Our Numbers.

- CHAPTER OVERVIEW -

Class 6 Maths Chapter 1 : Knowing Our Numbers contains 2 NCERT Exercises, and the Content available on this page provides Brief Explanation of this Chapter and solutions for the questions present in the NCERT Exercises. Now, let's look at some of the concepts which we have discuss in this chapter.

# Introduction to Numbers

Natural Numbers
Whole Numbers

# Reading & Writing Large Numbers

Numbers in Digits
Numbers in Words
Expanded Form
Place Value Chart
Use of Commas ( , )

# Comparing Numbers

Smaller V/s Greater ( <, >, = )

# Reordering of Numbers

Ascending & Descending order

# Making New Numbers

Shifting Digits

# Notation & Numeration

Indian System of Numeration
International System of Numeration

# Conversion of Units

Units of Length
Units of Mass
Units of Capacity

↓ SCROLL DOWN to get NCERT Solutions for Class 6 Maths Chapter 1 : Knowing Our Numbers.

# Short Notes :-

➡ Symbols like 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 are called Digits or Figures and a group of digits denoting a number is called a Numeral or a Number.

➡ Counting numbers 1, 2, 3, 4, 5, 6, ... etc. are known as Natural Numbers. Here '1' is the smallest natural number.

➡ The number '0' together with Natural numbers gives us Whole Numbers like 0, 1, 2, 3, 4, 5... etc. Here '0' is the smallest whole number.

➡ Face value of a digit in a number is the digit itself.

➡ Place value of a digit in a number = Its face value × Position value.

➡ The method of representing a number in digits or figures is called Notation and the method of expressing a number in words is called Numeration. There are two methods of numeration:

Indian system of numeration
International system of numeration.

➡ Conversion of Numbers & Units.

# Currency :

1 million = 10 lakhs
10 million = 1 crore
100 million = 10 crores
1 billion = 100 crores or 1 Arab.

# Length :

1 kilometer (km) = 1000 meter (m)
1 meter (m) = 100 centimetre (cm)
1 centimeter (cm) = 10 millimetre (mm)

# Mass :

1 kilogram (kg) = 1000 grams (g)
1 gram (g) = 1000 milligram (mg)

# Capacity :

1 kilolitre (kL) = 1000 litre (L)
1 litre (L) = 1000 millilitres (mL)

- NCERT SOLUTIONS -

NCERT Solutions for Class 6 Maths Chapter 1 : Knowing our Numbers are available here. we have prepared step by step solutions with detailed explanations. We advise students who want's to score good marks in Mathematics, to go through these solutions and strengthen their knowledge.

# NCERT Solutions for Ex - 1.1

Class 6 Maths Chapter 1 Exercise 1.1 Question 1.

Q1.  Fill in the blanks:

(a) 1 lakh =..…ten….. ten thousand.

(b) 1 million = ……ten…… hundred thousand.

(c) 1 crore = ……ten…… ten lakh.

(d) 1 crore = ……ten…… million.

(e) 1 million = ……ten…… lakh.

⛤  View Video Explanation
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Class 6 Maths Chapter 1 Exercise 1.1 Question 2.

Q2.  Place commas correctly & write numerals :
(a) Seventy-three lakh seventy-five thousand three hundred seven.
(b) Nine crore five lakh forty-one.
(c) Seven crore fifty-two lakh twenty-one thousand three hundred two.
(d) Fifty-eight million four hundred twenty- three thousand two hundred two.
(e) Twenty-three lakh thirty thousand ten.

Answer :

(a) Seventy-three lakh seventy-five thousand three hundred seven.
Solution :

Ans. 73,75,307

(b) Nine crore five lakh forty-one.
Solution :

Ans. 9,05,00,041

(c) Seven crore fifty-two lakh twenty-one thousand three hundred two.
Solution :

Ans. 7,52,21,302

(d) Fifty-eight million four hundred twenty- three thousand two hundred two.
Solution :

Ans. 5,84,23,202

(e) Twenty-three lakh thirty thousand ten.
Solution :

Ans. 23,30,010

⛤  View Video Explanation
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Class 6 Maths Chapter 1 Exercise 1.1 Question 3.

Q3.  Insert commas suitably and write the names according to Indian System of Numeration :
(a) 87595762
(b) 8546283
(c) 99900046
(d) 98432701

Solution :

(a) 87595762
Ans. 8,75,95,762 (Eight crore seventy-five lakh ninety-five thousand seven hundred sixty- two)

(b) 8546283
Ans. 85,46,283 (Eighty-five lakh forty-six thousand two hundred eighty-three)

(c) 99900046
Ans. 9,99,00,046 (Nine crore ninety-nine lakh forty-six)

(d) 98432701
Ans. 9,84,32,701 (Nine crore eighty-four lakh thirty-two thousand seven hundred one)

⛤  View Video Explanation
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Class 6 Maths Chapter 1 Exercise 1.1 Question 4.

Q4.  Insert commas suitably and write the names according to International System of Numeration:
(a) 78921092
(b) 7452283
(c) 99985102
(d) 48049831

Solution :

(a) 78921092
Ans. 78,921,092 (Seventy-eight million nine hundred twenty-one thousand ninety-two)

(b) 7452283
Ans. 7,452,283 (Seven million four hundred fifty- two thousand two hundred eighty-three)

(c) 99985102
Ans. 99,985,102 (Ninety-nine million nine hundred eighty-five thousand one hundred two)

(d) 48049831
Ans. 48,049,831 (Forty-eight million forty-nine thousand eight hundred thirty-one)

⛤  View Video Explanation

# NCERT Solutions for Ex - 1.2

Class 6 Maths Chapter 1 Exercise 1.2 Question 1.

Q1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Solution :

Number of tickets sold on the first day = 1094

Number of tickets sold on the second day = 1812

Number of tickets sold on the third day = 2050

Number of tickets sold on the final day = 2751

∴ Total number of tickets sold on all the four days = 1094 + 1812 + 2050 + 2751 = 7,707.

Ans. Total number of tickets sold on all the four days are 7,707.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 2.

Q2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Solution :

Shekhar has scored runs so far = 6980

Runs he wishes to complete = 10,000

Total number of runs needed by him = 10,000 – 6980 = 3020 runs

Ans. Total number of runs Shekhar needs are 3020

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 3.

Q3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Solution :

Number of Votes successful candidate registered = 5,77,500

Number of votes secured by his nearest rival = 3,48,700

Difference of votes between winner and rival = 5,77,500 – 3,48,700 = 2,28,800

Ans. Successful candidate win by 2,28,800 votes from his rival.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 4.

Q4. Kirti bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Solution :

Part 1 -

Books sold in first week of June worth ₹2,85,891

Books sold in second week of the month worth ₹4,00,768

∴ Total sale of books in the two weeks together = ₹2,85,891 + ₹4,00,768 = ₹6,86,659

Part 2 -

Books sold in first week of June worth ₹2,85,891

Books sold in second week of the month worth ₹4,00,768

Difference in the sale of books = ₹4,00,768 – ₹2,85,891 = ₹1,14,877

∴ In second week of June, the sale of books was more by ₹1,14,877.

Ans. They sold 6,86,659 books together in the two weeks and In the second week of the month, the sale of books was greater by 1,14,877 books.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 5.

Q5. Find the difference between the greatest and the least numbers that can be written using the digits 6, 2, 7, 4, 3 each only once.

Solution :

Given digits are 6, 2, 7, 4, 3

Greatest number = 76,432

Least number = 23,467

Difference = 76,432 – 23,467 = 52,965

Ans. The difference between the greatest and the least given numbers is 52,965.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 6.

Q6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January, 2006?

Solution :

Number of screws manufactured in a day = 2,825.

Number of days in month of January = 31 days

Number of screws manufactured in the month of January = 31 x 2825 = 87,575

Ans. Number of screws manufactured in the month of January is 87,575.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 7.

Q7. A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1200 each. How much money will remain with her after the purchase?

Solution :

Amount of money with the merchant = ₹78,592

Number of radio sets = 40

Price of one radio set = ₹1200

Therefore, cost of 40 radio sets = ₹1200 x 40 = ₹48,000

Amount of money remain with the merchant = ₹78,592 – ₹48000 = ₹30,592

Ans. Amount of ₹30,592 will remain with her after purchasing 40 radio sets.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 8.

Q8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?

Solution :

Student has multiplied 7236 by 65 instead of multiplying by 56. Difference between the two multiplications is -

= (65 – 56) x 7236

= 9 x 7236

= 65124

(We don’t need to do both the multiplication)

Ans. The answer is 65,124 greater than the correct answer.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 9.

Q9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?

Solution :

Total length of the cloth = 40 m ⇒ 40 x 100 cm = 4000 cm.

Cloth needed to stitch a shirt = 2 m 15 cm ⇒ 2 x 100 + 15 cm = 215 cm

Therefore, number of shirts stitched = 4000 ÷ 215 = 18

So, the number of shirts stitched = 18

The remaining cloth

= 4000 - (18 x 215)

= 4000 - 3870

= 130 cm

= 1 m 30 cm

Ans. The number of shirts stitched = 18 and the remaining cloth is 1 m 30 cm.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 10.

Q10. Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

Solution :

Weight of one box

= 4 kg 500 g

= 4 x 1000 + 500

= 4500 g

Maximum weight that van can carry

= 800 kg

= 800 x 1000

= 8,00,000 g

Therefore, number of boxes van can carry

= 8,00,000 ÷ 4500

= 177.777

Ans. The number of boxes that van can carry is 177.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 11.

Q11. The distance between the school and the house of a student is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.

Solution :

Distance between school and house

= 1 km 875 m

= (1000 + 875) m

= 1875 m.

Distance covered by the student both ways

= 2 x 1875

= 3750 m

Distance covered in 6 days

= 6 x 3750 m

= 22,500 m

= 22 km 500 m.

Ans. Total distance covered by student in six days is 22 km 500 m.

⛤ View Video Explanation

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Class 6 Maths Chapter 1 Exercise 1.2 Question 12.

Q12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

Solution :

Quantity of curd in a vessel

= 4 litre 500 ml

= (4 x 1000 ) + 500 ml

= 4500 ml

Capacity of 1 glass = 25 ml

∴ Number of glasses that can be filled

= 4500 ÷ 25

= 180

Ans. Number of glasses that can be filled by curd is 180.

⛤ View Video Explanation

# Class 6 Maths Chapter 1 : Extra Questions

class 6 maths chapter 1 extra questions.

Q1. Make the greatest and the smallest four digit number by using the digit 4,6,7 by repeating any digit twice.

Solution :

The greatest four Digit number is 7764
The smallest four Digit number is 4467

Explanation : To find the greatest four digit number we need to write the bigger number first and then the smaller number in decreasing order. On the other hand to find the smallest four digit number we start with smaller number and then arrange them in increasing order.

⛤ View Video Explanation

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extra questions for class 6 maths chapter 1.

Q2. The number of sheet of paper available for making notebook is 25000. Each sheet makes 12 pages of a notebook. Each notebook contain 300 pages. How many notebooks can be made from the paper available?

Solution :

Number of sheets available for making notebook = 25000

Number of Pages that each sheet makes = 12

∴ Total number of pages that can be made from all available sheets = 25000 x 12 = 3,00,000

Number of pages each notebook contains = 300

∴ Total Number of notebooks that can be made from all available pages = 3,00,000 ÷ 300 = 3000

Ans. 3000 notebooks can be made from the paper available.

⛤ View Video Explanation

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knowing our numbers class 6 extra questions.

Q3. Find the Product of place value of two Four’s in 643241.

Solution :

Place value of first 4 from right hand side = Tens = 40

Place value of second 4 from right hand side = Ten thousand = 40,000

The product of two place values of Four = 40 x 40,000 = 16,00,000

Ans. The product of two place values of Four is 16,00,000 ( Sixteen Lack)

⛤ View Video Explanation

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knowing our numbers class 6 questions and answers.

Q4. A box contains 5 strips having 12 capsules each of 500 mg medicine in each capsule. Find the (weight grams) of medicine in 32 such boxes.

Solution :

Weight of each capsule = 500 mg

Number of capsules in a Strip = 12

∴ Weight of each Strip = 12 x 500 = 6000 mg

Now,

Weight of each Strip = 6000 mg

Number of strips each box contain = 5

∴ Weight of each box = 5 x 6000 = 30,000 mg

Then,

Weight of 32 such boxes = 32 x 30,000 = 9,60,000 mg.

Ans. The weight of medicines in 32 boxes is 9,60,000 mg.

⛤ View Video Explanation

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knowing our numbers class 6 extra questions pdf.

Q5. Estimate the product 5981 x 4428 by rounding off each number to the nearest :

(i) ten

(ii) Hundreds

Solution :

(i) Rounding off to nearest ten = 5980 x 4430

= 2,64,91,400

(ii) Rounding off to nearest hundreds = 6000 x 4400

= 2,64,00,000

Ans. The estimate product for Nearest Ten is 2,64,91,400 and for nearest Hundred is 2,64,00,000

⛤ View Video Explanation

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class 6 maths chapter 1 extra questions.

Q6. India's population has been steadily increasing from 439 millions in 1961 to 1028 millions in 2001. Find the total increase in population from 1961 to 2001. Write the increase in population in Indian System of numeration using commas suitably.

Solution :

India's population in 1961 = 439 million

India's population in 2001 = 1028 million

∴ Increase in population = 1028 - 439 = 589 million

Now,

1 million = 10 lack

∴ Increase in population in Indian Numeration = 589 million x 10 lack = 5890 lack = 58,90,00,000

Ans. Increase in Indian population from 1961 to 2001 is 58,90,00,000 (Fifty Eight Crore Ninety Lack)

⛤ View Video Explanation

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extra questions for class 6 maths chapter 1.

Q7. A mobile number consists of ten digits. The First four digits of the number are 9,9,8,7. The last three digits are 3, 3 and 5. The remaining digits are distinct and makes the mobile number, the greatest possible number. What are these digits?

Solution :

The Digits that are available to make any number are 1, 2, 3, 4, 5, 6, 7, 8, 9.

Now,

The First four digits of the number are 9,9,8,7.

The last three digits are 3, 3 and 5.

∴ We have 7 digits out of a 10 digits mobile number.

So,

The remaining distinct digits are 1, 2, 4, 6 out of (1, 2, 3, 4, 5, 6, 7, 8, 9)

But,

We need greatest 3 digits out of 1, 2, 4, 6.

∴ We take 6, 4, 2 for our greatest 10 digit number.

Ans. The remaining distinct digits for greatest possible number are 6, 4, 2.

⛤ View Video Explanation

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knowing our numbers class 6 extra questions.

Q8. At rock concert there were 5500 spectators, out of which 750 were invites, who were given free tickets. The total collection from tickets was 5,93,750. what was the cost of One ticket?

Solution :

Total number of spectators at concert = 5500

Number of spectators who has invited for free = 750

∴ Number of spectators who bought tickets = 5500 - 750 = 4750

Now,

Total collection from tickets = 5,93,750

Number of spectators who bought tickets = 4750

∴ Cost of one ticket = 5,93,750 ÷ 5750 = 125

Ans. Cost of one ticket at concert is rupees 125.

⛤ View Video Explanation

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class 6 maths chapter 1 extra questions.

Q9. Estimate each of the following products by using general rule of estimation:

(a) 8 x 456

(b) 56797 - 3456

(c) 231 x 12345

(d) 2345 + 19

Solution :

(a) 8 x 456

Rounding off to nearest ten = 10 x 460 = 4600

(b) 56797 - 3456

Rounding off 56,797 to nearest hundreds = 56,800

Rounding off 3,456 to nearest hundreds = 3500

∴ 56,800 - 3500 = 53,300

Rounding off to nearest hundred

(d) 2345 + 19

Rounding off 2345 to nearest ten = 2350

Rounding off 19 to nearest ten = 20

∴ 2350 + 20 = 2370

⛤ View Video Explanation

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knowing our numbers class 6 questions and answers.

Q10. The population in a city is 4,90,50,102. Out of these 1,90,40,102 are men and 1,00,37,839 are women. Find the number of children in the city.

Solution :

Total population in a city = 4,90,50,102

Number of male population = 1,90,40,102

Number of female population = 1,00,37,839

Number of children in the city

= 4,90,50,102 - (1,90,40,102 + 1,00,37,839)

= 4,90,50,102 - 2,90,77,941

= 1,99,72,161

Ans. Population of children in the city is 1,99,72,161.

⛤ View Video Explanation

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extra questions for class 6 maths chapter 1.

Q11. Estimate each of the following by rounding off each number to –

(a) Nearest Hundreds : 7874 + 478

(b) Nearest Thousand : 96877 – 67783

Solution :

(a) Nearest Hundreds : 7874 + 478

Rounding off to nearest hundred

= 7900 + 500

= 8400

(b) Nearest Thousand : 96877 – 67783

Rounding off to nearest thousand

= 97000 - 68000

= 29000

⛤ View Video Explanation

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class 6 maths chapter 1 extra questions.

Q12. Determine the sum of three numbers given below :

(a) Successor of 37

(b) Predecessor of 59

(c) Predecessor of the Predecessor of 99

Solution :

(a) The Successor of 37 = 38

(b) The Predecessor of 59 = 58

Now,

∴ The Sum of Numbers = 38 + 58 + 97 = 193

⛤ View Video Explanation

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class 6 maths chapter 1 extra questions.

Q13. Write the numbers for following :

(a) Twelve million, Three hundred and sixty seven thousand, One hundred and sixty nine.

(b) Five million, Three hundred and Five thousand eight hundred and thirty two.

Ans.

(a) 12,367,169

(b) 5, 305,892

⛤ View Video Explanation

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knowing our numbers class 6 extra questions pdf.

Q14. Write the numbers in Indian System of Numeration :

(a) 40350894

(b) 279453

(c) 138943117

Ans.

(a) 4,03,50,894

(b) 2,79,453

Explanation : In Indian System of Numeration we first put comma after first three digits from last digit then we put commas after every two digits.

⛤ View Video Explanation

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class 6 maths chapter 1 extra questions.

Q15. Write the numbers in International System of Numeration :

(a) 138943117

(b) 342573

(c) 1465601

Solution :

(a) 138,943,117

(b) 342,573

Explanation : In International System of Numeration we put commas after every three digits from last digit.

⛤ View Video Explanation

# Class 6 Maths Chapter 1 : Fill ups.

class 6 maths chapter 1 Fill in the Blanks.

Q. In Indian System of Numeration, the number 61711682 is written, using commas, as 6,17,11,682 .

Q. The smallest 4 digit number with different digits is 1023 .

Q. 10 million = 1 crore.

Q. 10 lakh = 1 million.

Q. 1 metre = 1000 millimetres.

Q. 1 centimetre = 10 millimetres.

Q. 1 kilometre = 10,00,000 millimetres.

Q. 1 gram = 1000 milligrams.

Q. 1 litre = 1000 millilitres.

Q. 1 kilogram = 1000,000 miligrams.

Q. 100 thousands = 1 lakh.

Q. Height of a person is 1m 65cm. His height in millimetres is 1650 .

Q. Length of river ‘Narmada’ is about 1290km. Its length in metres is 1290000 .

Q. The distance between Sringar and Leh is 422km. The same distance in metres is 422000 .

Q. Writing of numbers from the greatest to the smallest is called an arrangement in descending order.

Q. By reversing the order of digits of the greatest number made by five different non-zero digits, the new number is the smallest number of five digits.

Q. By adding 1 to the greatest 6 digit number, we get ten lakh.

Q. The number five crore twenty three lakh seventy eight thousand four hundred one can be written, using commas, in the Indian System of Numeration as 5,23,78,401 .

Q. In Roman Numeration, the symbol X can be subtracted from L , M and C only.

Q. The number 66 in Roman numerals is LXVI .

Q. The population of Pune was 2,538,473 in 2001. Rounded off to nearest thousands, the population was 2,538,000 .

⛤ View Video Explanation

# Class 6 Maths Chapter 1 : True-False

class 6 maths chapter 1 True-False.

Q. The number 58963 rounded off to nearest hundred is 58900.

Ans. False.

Q. LXXV is greater than LXXIV.

Ans. True

Q. In Roman numeration, a symbol is not repeated more than three times.

Ans. True

Q. In Roman numeration, if a symbol is repeated, its value is multiplied as many times as it occurs.

Ans. False

Q. 5555 = 5 × 1000 + 5 × 100 + 5 × 10 + 5 × 1

Ans. True

Q. 39746 = 3 × 10000 + 9 × 1000 + 7 × 100 + 4 × 10 + 6

Ans. True

Q. 82546 = 8 × 1000 + 2 × 1000 + 5 × 100 + 4 × 10 + 6

Ans. False

Q. 532235 = 5 × 100000 + 3 × 10000 + 2 × 1000 + 2 × 100 + 3 × 10 + 5

Ans. True

Q. XXIX = 31

Ans. False

Q. LXXIV = 74

Ans. True

Q. The number LIV is greater than LVI.

Ans. False

Q. The numbers 4578, 4587, 5478, 5487 are in descending order.

Ans. False

Q. The number 85764 rounded off to nearest hundreds is written as 85700.

Ans. False

Q. Estimated sum of 7826 and 12469 rounded off to hundreds is 20,000.

Ans. True

Q. The largest six digit telephone number that can be formed by using digits 5, 3, 4, 7, 0, 8 only once is 875403.

Ans. False

Q. The number 81652318 will be read as eighty one crore six lakh fifty two thousand three hundred eighteen.

Ans. False

Q. The largest 4-digit number formed by the digits 6, 7, 0, 9 using each digit only once is 9760.

Ans. True

Q. Among kilo, milli and centi, the smallest is centi.

Ans. False

⛤ View Video Explanation

# Class 6 Maths Chapter 1 : MCQ's

class 6 maths chapter 1 MCQ's.

Q. 3 × 10000 + 0 × 1000 + 8 × 100 + 0 × 10 + 7 × 1 is same as

(A) 30087

(B) 30807

(C) 3807

(D) 3087

Q. 1 billion is equal to

(A) 100 millions

(B) 10 millions

(C) 1000 lakhs

(D) 10000 lakhs

Q. Which of the following numbers in Roman Numerals is incorrect?

(A) LXII

(B) XCI

(C) LC

(D) XLIV

Q. The product of the place values of two 2’s in 428721 is

(A) 4

(B) 40000

(C) 400000

(D) 40000000

Q. 3 × 10000 + 7 × 1000 + 9 × 100 + 0 ×10 + 4 is the same as

(A) 3794

(B) 37940

(C) 37904

(D) 379409

Q. If 1 is added to the greatest 7- digit number, it will be equal to

(A) 10 thousand

(B) 1 lakh

(C) 10 lakh

(D) 1 crore

Q. The expanded form of the number 9578 is

(A) 9 × 10000 + 5 × 1000 + 7 × 10 + 8 × 1

(B) 9 × 1000 + 5 × 100 + 7 × 10 + 8 × 1

(C) 9 × 1000 + 57 × 10 + 8 × 1

(D) 9 × 100 + 5 × 100 + 7 × 10 + 8 × 1

Q. When rounded off to nearest thousands, the number 85642 is

(A) 85600

(B) 85700

(C) 85000

(D) 86000

Q. The largest 4-digit number, using any one digit twice, from digits 5, 9, 2 and 6 is

(A) 9652

(B) 9562

(C) 9659

(D) 9965

Q. In Indian System of Numeration, the number 58695376 is written as

(A) 58,69, 53, 76

(B) 58,695,376

(C) 5,86,95,376

(D) 586,95,376

Q. One million is equal to

(A) 1 lakh

(B) 10 lakh

(C) 1 crore

(D) 10 crore

Q. The greatest number which on rounding off to nearest thousands gives 5000, is

(A) 5001

(B) 5559

(C) 5999

(D) 5499

Q. Keeping the place of 6 in the number 6350947 same, the smallest number obtained by rearranging other digits is

(A) 6975430

(B) 6043579

(C) 6034579

(D) 6034759

Q. Which of the following numbers in Roman numerals is incorrect?

(A) LXXX

(B) LXX

(C) LX

(D) LLX

Q. The largest 5-digit number having three different digits is

(A) 98978

(B) 99897

(C) 99987

(D) 98799

Q. The smallest 4-digit number having three different digits is

(A) 1102

(B) 1012

(C) 1020

(D) 1002

⛤ View Video Explanation

# Class 6 Maths Chapter 1 : MCQ Test

- SELF EVALUATION TEST -

This is a quiz based test which is consist of 25 Multiple Choice Questions to test your Understanding about Class 6 Maths Chapter 1 : Knowing Our Numbers.

online test for class 6 maths chapter 1

We hope that the given Study Material for Class 6 Maths Chapter 1 : Knowing Our Numbers will help you to understand the concepts with more clarity. But, If you have any query regarding Class 6 Maths Chapter 1 : Knowing Our Numbers then just ask your doubts in the section given below.

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