[Important Q's] Class 6 Maths Chapter 1 Knowing Our Numbers Extra Questions.
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# Class 6 Maths Chapter 1 - Knowing Our Numbers.
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Important Extra Questions for Class 6 Maths Chapter 1 :-
Here we have provided class 6 Maths chapter 1 Extra questions which includes extra questions for class 6 maths chapter 1. These questions are related to the topics that are discussed in the chapter knowing our numbers class 6 question and answers. We suggest you to go through these extra questions for class 6 maths chapter 1 to strengthen your understanding about knowing our numbers class 6 extra questions of class 6 mathematics.

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# Class 6 Maths Chapter 1 NCERT Book. (pdf)
# Class 6 Maths Chapter 1 Video Explanation.


# Class 6 Maths Chapter 1 : Extra Questions
class 6 maths chapter 1 extra questions.
Q1. Make the greatest and the smallest four digit number by using the digit 4,6,7 by repeating any digit twice.
Solution :
- The greatest four Digit number is 7764
- The smallest four Digit number is 4467
Explanation : To find the greatest four digit number we need to write the bigger number first and then the smaller number in decreasing order. On the other hand to find the smallest four digit number we start with smaller number and then arrange them in increasing order.
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extra questions for class 6 maths chapter 1.
Q2. The number of sheet of paper available for making notebook is 25000. Each sheet makes 12 pages of a notebook. Each notebook contain 300 pages. How many notebooks can be made from the paper available?
Solution :
Number of sheets available for making notebook = 25000
Number of Pages that each sheet makes = 12
∴ Total number of pages that can be made from all available sheets = 25000 x 12 = 3,00,000
Number of pages each notebook contains = 300
∴ Total Number of notebooks that can be made from all available pages = 3,00,000 ÷ 300 = 3000
Ans. 3000 notebooks can be made from the paper available.
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knowing our numbers class 6 extra questions.
Q3. Find the Product of place value of two Four’s in 643241.
Solution :
Place value of first 4 from right hand side = Tens = 40
Place value of second 4 from right hand side = Ten thousand = 40,000
The product of two place values of Four = 40 x 40,000 = 16,00,000
Ans. The product of two place values of Four is 16,00,000 ( Sixteen Lack)
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knowing our numbers class 6 questions and answers.
Q4. A box contains 5 strips having 12 capsules each of 500 mg medicine in each capsule. Find the (weight grams) of medicine in 32 such boxes.
Solution :
Weight of each capsule = 500 mg
Number of capsules in a Strip = 12
∴ Weight of each Strip = 12 x 500 = 6000 mg
Now,
Weight of each Strip = 6000 mg
Number of strips each box contain = 5
∴ Weight of each box = 5 x 6000 = 30,000 mg
Then,
Weight of 32 such boxes = 32 x 30,000 = 9,60,000 mg.
Ans. The weight of medicines in 32 boxes is 9,60,000 mg.
⇒ View Explanation
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knowing our numbers class 6 extra questions pdf.
Q5. Estimate the product 5981 x 4428 by rounding off each number to the nearest :
(i) ten
(ii) Hundreds
Solution :
(i) Rounding off to nearest ten = 5980 x 4430
= 2,64,91,400
(ii) Rounding off to nearest hundreds = 6000 x 4400
= 2,64,00,000
Ans. The estimate product for Nearest Ten is 2,64,91,400 and for nearest Hundred is 2,64,00,000
⇒ View Explanation
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class 6 maths chapter 1 extra questions.
Q6. India's population has been steadily increasing from 439 millions in 1961 to 1028 millions in 2001. Find the total increase in population from 1961 to 2001. Write the increase in population in Indian System of numeration using commas suitably.
Solution :
India's population in 1961 = 439 million
India's population in 2001 = 1028 million
∴ Increase in population = 1028 - 439 = 589 million
Now,
1 million = 10 lack
∴ Increase in population in Indian Numeration = 589 million x 10 lack = 5890 lack = 58,90,00,000
Ans. Increase in Indian population from 1961 to 2001 is 58,90,00,000 (Fifty Eight Crore Ninety Lack)
⇒ View Explanation
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extra questions for class 6 maths chapter 1.
Q7. A mobile number consists of ten digits. The First four digits of the number are 9,9,8,7. The last three digits are 3, 3 and 5. The remaining digits are distinct and makes the mobile number, the greatest possible number. What are these digits?
Solution :
The Digits that are available to make any number are 1, 2, 3, 4, 5, 6, 7, 8, 9.
Now,
The First four digits of the number are 9,9,8,7.
The last three digits are 3, 3 and 5.
∴ We have 7 digits out of a 10 digits mobile number.
So,
The remaining distinct digits are 1, 2, 4, 6 out of (1, 2, 3, 4, 5, 6, 7, 8, 9)
But,
We need greatest 3 digits out of 1, 2, 4, 6.
∴ We take 6, 4, 2 for our greatest 10 digit number.
Ans. The remaining distinct digits for greatest possible number are 6, 4, 2.
⇒ View Explanation
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knowing our numbers class 6 extra questions.
Q8. At rock concert there were 5500 spectators, out of which 750 were invites, who were given free tickets. The total collection from tickets was 5,93,750. what was the cost of One ticket?
Solution :
Total number of spectators at concert = 5500
Number of spectators who has invited for free = 750
∴ Number of spectators who bought tickets = 5500 - 750 = 4750
Now,
Total collection from tickets = 5,93,750
Number of spectators who bought tickets = 4750
∴ Cost of one ticket = 5,93,750 ÷ 5750 = 125
Ans. Cost of one ticket at concert is rupees 125.
⇒ View Explanation
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class 6 maths chapter 1 extra questions.
Q9. Estimate each of the following products by using general rule of estimation:
(a) 8 x 456
(b) 56797 - 3456
(c) 231 x 12345
(d) 2345 + 19
Solution :
(a) 8 x 456
Rounding off to nearest ten = 10 x 460 = 4600
(b) 56797 - 3456
Rounding off 56,797 to nearest hundreds = 56,800
Rounding off 3,456 to nearest hundreds = 3500
∴ 56,800 - 3500 = 53,300
(c) 231 x 12345
Rounding off to nearest hundred
(d) 2345 + 19
Rounding off 2345 to nearest ten = 2350
Rounding off 19 to nearest ten = 20
∴ 2350 + 20 = 2370
⇒ View Explanation
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knowing our numbers class 6 questions and answers.
Q10. The population in a city is 4,90,50,102. Out of these 1,90,40,102 are men and 1,00,37,839 are women. Find the number of children in the city.
Solution :
Total population in a city = 4,90,50,102
Number of male population = 1,90,40,102
Number of female population = 1,00,37,839
Number of children in the city
= 4,90,50,102 - (1,90,40,102 + 1,00,37,839)
= 4,90,50,102 - 2,90,77,941
= 1,99,72,161
Ans. Population of children in the city is 1,99,72,161.
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extra questions for class 6 maths chapter 1.
Q11. Estimate each of the following by rounding off each number to –
(a) Nearest Hundreds : 7874 + 478
(b) Nearest Thousand : 96877 – 67783
Solution :
(a) Nearest Hundreds : 7874 + 478
Rounding off to nearest hundred
= 7900 + 500
= 8400
(b) Nearest Thousand : 96877 – 67783
Rounding off to nearest thousand
= 97000 - 68000
= 29000
⇒ View Explanation
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class 6 maths chapter 1 extra questions.
Q12. Determine the sum of three numbers given below :
(a) Successor of 37
(b) Predecessor of 59
(c) Predecessor of the Predecessor of 99
Solution :
(a) The Successor of 37 = 38
(b) The Predecessor of 59 = 58
(c) The Predecessor of the Predecessor of 99 = 97
Now,
∴ The Sum of Numbers = 38 + 58 + 97 = 193
⇒ View Explanation
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class 6 maths chapter 1 extra questions.
Q13. Write the numbers for following :
(a) Twelve million, Three hundred and sixty seven thousand, One hundred and sixty nine.
(b) Five million, Three hundred and Five thousand eight hundred and thirty two.
Ans.
(a) 12,367,169
(b) 5, 305,892
⇒ View Explanation
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knowing our numbers class 6 extra questions pdf.
Q14. Write the numbers in Indian System of Numeration :
(a) 40350894
(b) 279453
(c) 138943117
Ans.
(a) 4,03,50,894
(b) 2,79,453
(c) 13,89,43,117
Explanation : In Indian System of Numeration we first put comma after first three digits from last digit then we put commas after every two digits.
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class 6 maths chapter 1 extra questions.
Q15. Write the numbers in International System of Numeration :
(a) 138943117
(b) 342573
(c) 1465601
Solution :
(a) 138,943,117
(b) 342,573
(c) 1,465,601
Explanation : In International System of Numeration we put commas after every three digits from last digit.
⇒ View Explanation

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