[Exercise 1.3] NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers.
🏠 Home > Learn Maths > Class 6 Maths > Chapter 1 : Knowing Our Numbers > Exercise 1.3 Solutions.
# Class 6 Maths Chapter 1 - Knowing Our Numbers.
 |
| - Watch this video for Explanation - |
Maths Class 6 Chapter 1 Exercise 1.3 Solutions :-
Here we have provided exercise 1.3 class 6th Maths chapter 1 NCERT Solutions which includes NCERT Solutions for exercise 1.3 class 6 maths chapter 1 solutions. These questions are related to ex 1.3 class 6 chapter 1 knowing our numbers. We suggest you to go through these NCERT Solutions for class 6 maths chapter 1 to strengthen your understanding about knowing our numbers class 6 exercise 1.3 of class 6 mathematics.
Here at MSEducator.in you get Complete FREE Study Material for Class 6 Maths Chapter 1 : Knowing Our Numbers.
Which Includes :-
# Class 6 Maths Chapter 1 NCERT Book. (pdf)
# Class 6 Maths Chapter 1 Video Explanation.
# NCERT Solutions for Ex - 1.3
Class 6 Maths Chapter 1 Exercise 1.3 Question 1.
Q1. Estimate each of the following using general rule :
(a) 730 + 998
(b) 796 – 314
(c) 12,904 + 2,888
(d) 28,292 – 21,496
Make ten more such examples of addition, subtraction and estimation of their outcome.
Solution :
(a) 730 + 998
Rounding off 730 to nearest hundreds = 700
Rounding off 998 to nearest hundreds = 1,000
∴ 730 + 998 = 700 + 1000 = 1700
(b) 796 – 314
Rounding off 796 to nearest hundreds = 800
Rounding off 314 to nearest hundreds = 300
∴ 796 – 314 = 800 – 300 = 500
(c) 12,904 + 2,888
Rounding off 12,904 to nearest thousands = 13000
Rounding off 2888 to nearest thousands = 3000
∴ 12,904 + 2,888 = 13000 + 3000 = 16000
(d) 28,292 – 21,496
Rounding off 28,292 to nearest thousands = 28,000
Rounding off 21,496 to nearest thousands = 21,000
∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000
⛤ View Video Explanation
--------------------------------
# 10 More Examples :
(a) 1225 + 2375
Rounding off 1225 to nearest thousand = 1000
Rounding off 2375 to nearest thousand = 2000
∴ 1000 + 2000 = 3000
(b) 3853 + 6824
Rounding off 3853 to nearest thousand = 4000
Rounding off 6824 to nearest thousand = 7000
∴ 4000 + 7000 = 11,000
(c) 8752 – 3654
Rounding off 8752 to nearest thousand = 9000
Rounding off 3654 to nearest thousand = 4000
∴ 9,000 – 4,000 = 5,000
(d) 4538 – 2965
Rounding off 4538 to nearest thousand = 5000
Rounding off 2965 to nearest thousand = 3000
∴ 5,000 – 3,000 = 2,000
(e) 1927 + 3185
Rounding off 1927 to nearest thousand = 2000
Rounding off 3185 to nearest thousand = 3000
∴ 2000 + 3,000 = 5,000
(f) 3258 – 1698
Rounding off 3258 to nearest thousand = 3000
Rounding off 1698 to nearest thousand = 2000
∴ 3000 – 2000 = 1,000
(g) 8735 + 6232
Rounding off 8735 to nearest thousand = 9000
Rounding off 6232 to nearest thousand = 6000
∴ 9000 + 6000 = 15,000
(h) 1038 – 1028
Rounding off 1038 to nearest thousand = 1000
Rounding off 1028 to nearest thousand = 1000
∴ 1000 – 1000 = 0
(i) 6352 + 5830
Rounding off 6352 to nearest thousand = 6000
Rounding off 5830 to nearest thousand = 6000
∴ 6,000 + 6,000 = 12,000
(j) 9854 – 6385
Rounding off 9854 to nearest thousand = 10,000
Rounding off 6385 to nearest thousand = 6000
∴ 10,000 – 6000 = 4,000
⛤ View Video Explanation
--------------------------------
Class 6 Maths Chapter 1 Exercise 1.3 Question 2.
Q2. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a) 439 + 334 + 4,317
(b) 1,08,734-47,599
(c) 8,325-491
(d) 4,89,348-48,365
Make four such examples:
Solution :
(a) 439 + 334 + 4,317
(i) Rough estimate (Rounding off to nearest hundreds)
= 439 + 334 + 4,317
= 400 + 300 + 4300
= 5,000
(ii) Closer estimate (Rounding off to nearest tens)
= 439 + 334 + 4317
= 440 + 330 + 4320
= 5090.
(b) 1,08,734 – 47,599
(i) Rough estimate (Rounding off to nearest hundreds)
= 1,08,734 – 47,599
= 1,08,700 – 47,600
= 61,100
(ii) Closer estimate (Rounding off to nearest tens)
= 1,08,734 – 47,599
= 1,08,730 – 47,600
= 61,130.
(c) 8325 – 491
(i) Rough estimate (Rounding off to nearest hundreds)
= 8325 – 491
= 8300 – 500
= 7800
(ii) Closer estimate (Rounding off to nearest tens)
= 8325 – 491
= 8330 – 490
= 7840.
(d) 4,89,348 – 48,365
(i) Rough estimate (Rounding off to nearest hundreds)
= 4,89,348 – 48,365
= 4,89,300 – 48,400
= 4,40,900
(ii) Closer estimate (Rounding off to nearest tens)
= 4,89,348 – 48,365
= 4,89,350 – 48,370
= 4,40,980
⛤ View Video Explanation
--------------------------------
# 4 More Examples :
(a) 384 + 562
(i) Rough estimate (Rounding off to nearest hundreds)
= 384 + 562
= 400 + 600
= 1,000
(ii) Closer estimate (Rounding off to nearest tens)
= 384 + 562
= 380 + 560
= 940
(b) 8765 – 3820
(i) Rough estimate (Rounding off to nearest hundreds)
= 8765 – 3820
= 8800 – 3800
= 5000
(ii) Closer estimate (Rounding off to nearest tens)
= 8765 – 3820
= 8770 – 3820
= 4950
(c) 6653 – 8265
(i) Rough estimate (Rounding off to nearest hundreds)
= 6653 + 8265
= 6700 + 8300
= 15,000
(ii) Closer estimate (Rounding off to nearest tens)
= 6653 + 8265
= 6650 + 8270
= 14,920
(d) 3826 – 1262
(i) Rough estimate (Rounding off to nearest hundreds)
= 3826 – 1262
= 3800 – 1300
= 2500
(ii) Closer estimate (Rounding off to nearest tens)
= 3826 – 1262
= 3830 – 1260
= 2570
⛤ View Video Explanation
--------------------------------
Class 6 Maths Chapter 1 Exercise 1.3 Question 3.
Q3. Estimate the following products using general rule :
(a) 578 x 161
(b)5281 x 3491
(c) 1291 x 592
(d) 9250 x 29
Make four more such examples.
Solution :
(a) 578 x 161
Rounding off to nearest hundred
= 600 x 200
= 1,20,000
(b) 5281 x 3491
Rounding off to nearest thousand
= 5000 x 3000
= 1,50,00,000
(c) 1291 x 592
Rounding off to nearest thousand & hundred
= 1000 x 600
= 6,00,000
(d) 9250 x 29
Rounding off to nearest Thousand and Ten
= 9000 x 30
= 2,70,000
⛤ View Video Explanation
--------------------------------
# 4 More Examples :
(a) 382 x 1062
Rounding off to nearest Hundred and Thousand
= 400 x 1000
= 4,00,000
(b) 6821 x 1291
Rounding off to nearest Thousand
= 7000 x 1000
= 70,00,000
(c) 3858 x 9350
Rounding off to nearest Thousand
= 4000 x 9000
= 3,60,00,000
(d) 3405 x 7502
Rounding off to nearest Thousand
= 3000 x 8000
= 2,40,00,000
⛤ View Video Explanation
We hope that the given Study Material for Class 6 Maths Chapter 1 Knowing Our Numbers will help you to understand the concepts with more clarity. But, If you have any query regarding Class 6 Maths Chapter 1 Knowing Our Numbers then just ask your doubts in the section given below.
Tagged with - Class 6th maths chapter 1, class 6 maths chapter 1, class 6 maths chapter 1 pdf, knowing our numbers, ncert maths class 6 pdf, ncert class 6 maths pdf, knowing our numbers class 6, knowing our numbers class 6 worksheet, class 6 chapter 1, class 6 maths chapter 1 worksheet, ncert maths book class 6 chapter 1 solutions, ncert class 6 maths chapter 1, class 6 maths chapter 1 questions and answers, 6th class maths chapter 1, class 6 chapter 1 maths, exercise 1.3 class 6th, exercise 1.3 class 6, ex 1.3 class 6, maths class 6 chapter 1 exercise 1.3 solutions, exercise 1.3 class 6 maths, ex 1.3 class 6 maths ncert solutions, class 6 maths chapter 1 exercise 1.3 solutions, class 6 maths exercise 1.3 solutions.
# Still have some Doubts?
-- Feel FREE to Ask your Doubts here --
CLASS 6 LITERATURE