[Exercise 2.2] NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers.
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# Class 6 Maths Chapter 2 - Whole Numbers.
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Maths Class 6 Chapter 2 Exercise 2.2 Solutions :-
Here we have provided class 6 Maths chapter 2 Exercise 2.2 Solutions which includes NCERT Solutions for class 6 maths chapter 2 exercise 2.2. These questions are related to the topics that are discussed in the chapter whole numbers class 6 chapter 2. We suggest you to go through these NCERT Solutions for class 6 maths chapter 2 to strengthen your understanding about knowing our numbers class 6 exercise 2.2 of class 6 mathematics.
Here at MSEducator.in you get Complete FREE Study Material for Class 6 Maths Chapter 2 : Whole Numbers.
Which Includes :-
# Class 6 Maths Chapter 2 NCERT Book. (pdf)
# Class 6 Maths Chapter 2 Video Explanation.
# NCERT Solutions for Ex - 2.2
Class 6 Maths Chapter 1 Exercise 2.2 Question 1.
Q1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
Solution :
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
Solution :
= (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 2.
Q2. Find the product by suitable rearrangement :
(a) 2 × 1768 × 50
Solution :
= 2 × 50 × 1768
= 100 × 1768
= 176800
(b) 4 × 166 × 25
Solution :
= 4 × 25 × 166
= 100 × 166
= 16600
(c) 8 × 291 × 125
Solution :
= 8 × 125 × 291
= 1000 × 291
= 291000
(d) 625 × 279 × 16
Solution :
= 625 × 16 × 279
= 10000 × 279
= 2790000
(e) 285 × 5 × 60
Solution :
= 285 × 300
= 85500
(f) 125 × 40 × 8 × 25
Solution :
= 125 × 8 × 40 × 25
= 1000 × 1000
= 1000000
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 3.
Q3. Find the value of the following :
(a) 297 × 17 + 297 × 3
Solution :
= 297 x (17 + 3)
= 297 x 20
= 297 x 2 x 10
= 594 x 10
= 5940
(b) 54279 × 92 + 8 × 54279
Solution :
= 54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 × 169 – 81265 × 69
Solution :
= 81265 × (169 – 69)
= 81265 × 100
= 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
Solution :
= (3845 × 5 × 782) + (769 × 5 × 5 × 218)
= (3845 × 5 × 782) + (3845 × 5 × 218)
= (3845 × 5) × (782 + 218)
= 19225 × 1000
= 19225000
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 4.
Q4. Find the product using suitable properties.
(a) 738 × 103
Solution :
By using distributive property
= 738 x (100 + 3)
= 738 x 100 + 738 x 3
= 73800 + 2214
= 76014
(b) 854 × 102
Solution :
By using distributive property
= 854 x (100 + 2)
= 854 x 100 + 854 x 2
= 85400 + 1708
= 87108
(c) 258 × 1008
Solution :
By using distributive property
= 258 x (1000 + 8)
= 258 x 1000 + 258 x 8
= 258000 + 2064 = 260064
(d) 1005 × 168
Solution :
By using distributive property
= (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840 = 168840
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 5.
Q5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs rupees 44 per litre, how much did he spend in all on petrol?
Solution :
Cost of petrol = Rs.44 per litre
Petrol filled on Monday = 40 litre
Petrol filled on Tuesday = 50 litre
Total money spent on petrol -
= (40 + 50) x 44
= 90 x 44
= Rs.3960
Ans. Total money he Spend on petrol is Rs. 3960.
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 6.
Q6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs rupees 45 per litre, how much money is due to the vendor per day?
Solution :
Cost of milk = Rs.45 per litre
Milk supplied in the morning = 32 litre
Milk supplied in the evening = 68 litre
Money due to the vendor per day -
= (32 + 68) x 45
= 100 x 45
= Rs.4500
Ans. Total money due to the vendor per day is rupees 4500.
⇒ View Explanation
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Class 6 Maths Chapter 1 Exercise 2.2 Question 7.
Q7. Match the following :
Answer.
⇒ View Explanation
We hope that the given Study Material for Class 6 Maths Chapter 2 whole Numbers will help you to understand the concepts with more clarity. But, If you have any query regarding Class 6 Maths Chapter 2 whole Numbers then just ask your doubts in the section given below.
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